Thread: 48/2(9+3) = ???
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Old April 8th, 2011, 03:12 AM   #42 (permalink)
JeffTD
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Quote:
Originally Posted by Morgan C View Post
Ok what if we split it up.

2x and 2*x are the exact same thing, right? Or are even those 'paired'? I need a source on this, because it's just not right.

Lets make it 48/2(x), where x=9+3. Same equation.

= 48 / 2 (x)
= 48 2 * x
= 24 * x
= 24 * (9+3)
= 288.

Unless you can provide some proof that a / sign means that absolutely everything in the entire equation following that sign is now a denominator, or that 2x != 2*x, or at least 2*x is not 'as important' as 2x, then I don't know what to say.
Like I said, it sounds retarded isolated but it changes how the equations react.

I know that 2 is 'latched' to (9+3) because it's written as 2(9+3) and not 2*(9+3).

In your example, you need to solve for X first, because it's 2 quantities of x, not just 2 times x. The isolated product is the same, but you need to do it first to simplify the equation.



Deryk, I know FOIL is for two separate binomials... don't really give a fuck in this case, it's the same logic.



mortum, we can't assume the problem is written as anything really, because it wasn't written - it was typed. That's why we're running into issues. If this person wrote it out in standard notation, it'd be obvious as to which term was a denominator and which was supposed to be dealt with after the division. In this case, since it's written as 2(9+3), as per my explanations above, we have to assume that it's (48)/(2(9+3)).

In the math classes you'd have taken, the professor (hopefully) wouldn't be dumb enough to be as ambiguous as the author of this equation.
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Last edited by JeffTD : April 8th, 2011 at 03:14 AM.
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